Showing posts with label iPod. Show all posts
Showing posts with label iPod. Show all posts
Saturday, August 15, 2009
Be aware all iPhone users: The device is a time bomb!
Keep your distant for all the iPhone user around you. The iPhone may explode anytime. Don’t believe me? Read the rest of the story below. Just recently, another headlines sounded like this, “Yet another exploding iPhone”. This incident happens to a French teenager, when his girlfriend’s iPhone screen suddenly exploded, just a week ago Apple was accused of trying to suppress news of an
Tuesday, July 15, 2008
iPhone/iPod Bluetooth A2DP Stereo Audio Transmitter
Dá-lhe,
Querendo ouvir suas música no iPhone (iPod) via A2DP?
Seu problema acabou.
A Brando (conhecida loja online de acessórios e afins de Hong Kong) acaba de lançar o:
The Smallest iPhone / iPod Bluetooth A2DP Stereo Audio Transmitter
(INFINXX AP23)
(INFINXX AP23)
Com esse pequeno acessório você poderá ouvir suas músicas favoritas no seu fone Stereo via Bluetooth (A2DP).
Ele funciona tanto no iPhone, como no novo iPhone 3G e no iPod.
Vejam as especificações e mais fotos logo abaixo:
Features:
Specifications:
Package Content:
PREÇO: U$62
Onde comprar: Brando
Mais Fotos
Monday, December 31, 2007
The Twelve Days of Christmas: Day 7
Jeremy's Status Message Proudly Presents The Twelve Days of Christmas:
On the seventh day of Christmas,
My new iPod gave to me,
Seven Mary Three
Sixpence None The Richer
Five for Fighting,
The Four Tops,
Three Doors Down
Two Skinnee J's,
And nothing by the Partridge Family, so don't even joke about it.
Explanation: Also on my new iPod are:
Seven One Eight, by the 2 Skinnee J's
Six Underground, by the Sneaker Pimps
Five Piece Chicken Dinner, by the Beastie Boys
Four Sticks, by Led Zeppelin
Three MCs and one DJ, by the Beastie Boys
Two Step, by the Dave Matthews Band
And The Humpty Dance, by Digital Underground.
Yeah, that's right - The Humpty Dance. It has nothing to do with partridges or pear trees. It's just a cool song.
Special Blog Bonus: Feeling numerical? Don't forget 5150 by Van Halen, #41 by the Dave Matthews Band, 50 Ways to Leave Your Lover by Paul Simon, 8 Mile by Eminem, 316 by Van Halen, 99 Problems by Jay-Z, 1979 by the Smashing Pumpkins, 1984 by Van Halen, Nineteen Naughty Three by Naughty By Nature, 100 Years by Five for Fighting, One Thing by Finger Eleven, 3 A.M. Eternal by the KLF, Ten by Pearl Jam, and 6th Avenue Heartache by the Wallflowers. Speaking of numerical...
Solutions to Yesterday's Evil Number Theory Questions:
6 is the smallest perfect number, because it is equal to the sum of its proper positive divisors: 1, 2, and 3. Can you find the next even perfect number? Can you find an odd perfect number?
The next even perfect number is 28, which is the sum of 1, 2, 4, 7, and 14. The perfect numbers after that are 496 and 8128. All known perfect numbers fit the formula 2^(n-1) * (2^n - 1) where 2^(n-1) is a Mersenne prime. It is unknown whether there are any odd perfect numbers. If you managed to find one, you should tell me what it is and never speak of it again.
5 is a prime number whose binary representation, "101" is palindromic, meaning its digits read the same backward as forward. What is the largest known prime number that is palindromic in binary?
The largest known prime number which is palindromic in binary is 2^32582657, which is a 9.8 million digit number and happens to be the largest prime number known to date. It is a Mersenne prime, meaning it is one less than a power of two, hence the binary representation of the number is a string of ones, and is therefore the same both backward and forward. All of the largest known primes are Mersenne primes.
4 is an even integer that can be written as the sum of two primes, namely 2 and 2. Can you find an even integer that cannot?
This little gem is called Goldbach's conjecture. It is a conjecture because it is unproven. If you have found an integer that cannot, again, please contact me immediately with that number and then treat yourself to a nice long vacation in a place without telephones while I hold onto it all safe and sound for you. Don't worry. I won't tell anyone.
3 is a triangular number, because it belongs to the sequence (1, 3, 6, 10, 15, 21, ...). The number 3 can be represented as a sum of three triangular numbers: 3 = 1 + 1 + 1. Can you find an integer that cannot?
No you cannot. This is a subset of the Fermat polygonal number theorem, which states that every positive integer is the sum of at most n n-polygonal numbers. So, in this case, n=3.
2 is a value for n such that there exist nonzero integers x, y, and z where x^n + y^n = z^n. For example, 3^2 + 4^2 = 5^2. Can you find a value of n greater than 2 for which this is also true?
This would be Fermat's Last Theorem. Pierre de Fermat famously wrote the following words in the margin of a book: "It is impossible to separate a cube into two cubes, or a fourth power into two fourth powers, or in general, any power higher than the second into two like powers. I have discovered a truly marvelous proof of this, which this margin is too narrow to contain." For over 350 years, mathematicians cursed this man and his "marvelous proof", until Andrew Wiles of Princeton published a proof in 1995. Anyway, in short, the answer to this question is "No, you cannot".
1 is the difference between 2 and 3. There also exist powers of 2 and 3 such that their difference is also 1, namely 2^3=8 and 3^2=9. Can you find another pair of consecutive integers who have powers that are also consecutive?
This problem was known as Catalan's conjecture for over 150 years until it was solved by Preda Mihăilescu in 2002, and it is now referred to by the much more pronounceable "Mihăilescu's theorem." The example I cited shows the only pair of consecutive integers (2 and 3) for which this is possible. So, if you found another pair of consecutive integers, I suggest you check your math.
On the seventh day of Christmas,
My new iPod gave to me,
Seven Mary Three
Sixpence None The Richer
Five for Fighting,
The Four Tops,
Three Doors Down
Two Skinnee J's,
And nothing by the Partridge Family, so don't even joke about it.
Explanation: Also on my new iPod are:
Seven One Eight, by the 2 Skinnee J's
Six Underground, by the Sneaker Pimps
Five Piece Chicken Dinner, by the Beastie Boys
Four Sticks, by Led Zeppelin
Three MCs and one DJ, by the Beastie Boys
Two Step, by the Dave Matthews Band
And The Humpty Dance, by Digital Underground.
Yeah, that's right - The Humpty Dance. It has nothing to do with partridges or pear trees. It's just a cool song.
Special Blog Bonus: Feeling numerical? Don't forget 5150 by Van Halen, #41 by the Dave Matthews Band, 50 Ways to Leave Your Lover by Paul Simon, 8 Mile by Eminem, 316 by Van Halen, 99 Problems by Jay-Z, 1979 by the Smashing Pumpkins, 1984 by Van Halen, Nineteen Naughty Three by Naughty By Nature, 100 Years by Five for Fighting, One Thing by Finger Eleven, 3 A.M. Eternal by the KLF, Ten by Pearl Jam, and 6th Avenue Heartache by the Wallflowers. Speaking of numerical...
Solutions to Yesterday's Evil Number Theory Questions:
6 is the smallest perfect number, because it is equal to the sum of its proper positive divisors: 1, 2, and 3. Can you find the next even perfect number? Can you find an odd perfect number?
The next even perfect number is 28, which is the sum of 1, 2, 4, 7, and 14. The perfect numbers after that are 496 and 8128. All known perfect numbers fit the formula 2^(n-1) * (2^n - 1) where 2^(n-1) is a Mersenne prime. It is unknown whether there are any odd perfect numbers. If you managed to find one, you should tell me what it is and never speak of it again.
5 is a prime number whose binary representation, "101" is palindromic, meaning its digits read the same backward as forward. What is the largest known prime number that is palindromic in binary?
The largest known prime number which is palindromic in binary is 2^32582657, which is a 9.8 million digit number and happens to be the largest prime number known to date. It is a Mersenne prime, meaning it is one less than a power of two, hence the binary representation of the number is a string of ones, and is therefore the same both backward and forward. All of the largest known primes are Mersenne primes.
4 is an even integer that can be written as the sum of two primes, namely 2 and 2. Can you find an even integer that cannot?
This little gem is called Goldbach's conjecture. It is a conjecture because it is unproven. If you have found an integer that cannot, again, please contact me immediately with that number and then treat yourself to a nice long vacation in a place without telephones while I hold onto it all safe and sound for you. Don't worry. I won't tell anyone.
3 is a triangular number, because it belongs to the sequence (1, 3, 6, 10, 15, 21, ...). The number 3 can be represented as a sum of three triangular numbers: 3 = 1 + 1 + 1. Can you find an integer that cannot?
No you cannot. This is a subset of the Fermat polygonal number theorem, which states that every positive integer is the sum of at most n n-polygonal numbers. So, in this case, n=3.
2 is a value for n such that there exist nonzero integers x, y, and z where x^n + y^n = z^n. For example, 3^2 + 4^2 = 5^2. Can you find a value of n greater than 2 for which this is also true?
This would be Fermat's Last Theorem. Pierre de Fermat famously wrote the following words in the margin of a book: "It is impossible to separate a cube into two cubes, or a fourth power into two fourth powers, or in general, any power higher than the second into two like powers. I have discovered a truly marvelous proof of this, which this margin is too narrow to contain." For over 350 years, mathematicians cursed this man and his "marvelous proof", until Andrew Wiles of Princeton published a proof in 1995. Anyway, in short, the answer to this question is "No, you cannot".
1 is the difference between 2 and 3. There also exist powers of 2 and 3 such that their difference is also 1, namely 2^3=8 and 3^2=9. Can you find another pair of consecutive integers who have powers that are also consecutive?
This problem was known as Catalan's conjecture for over 150 years until it was solved by Preda Mihăilescu in 2002, and it is now referred to by the much more pronounceable "Mihăilescu's theorem." The example I cited shows the only pair of consecutive integers (2 and 3) for which this is possible. So, if you found another pair of consecutive integers, I suggest you check your math.
Tuesday, October 2, 2007
Tuesday, August 21, 2007
¿Por qué el iPhone tardará en llegar a España?
Me comentan por aquí que España es el paraíso europeo de los teléfonos móviles, que en ningún rincón del viejo continente la gente se gasta la pasta que nosotros nos gastamos en nuevos terminales y politonos y demás. Sin embargo, hoy parece confirmarse un viejo rumor y según Financial Times, España no estará entre los países europeos que podrán disfrutar del iPhone de Apple en su primer estreno europeo.
En los foros de usuarios de Mac y de amantes de Apple, los usuarios ya estamos de luto mientras nos replanteamos nuestro amor por Steve Jobs.
Pero, ¿qué hace que un mercado tan suculento como el nuestro espante al fabrica
nte del móvil de todos los móviles, aquel por el que la gente dormía en la calle para poder comprarlo cuando se lanzó en USA?. Yo tengo una respuesta a eso: la piratería.
España no es un buen territorio para las ventas de Apple, y no ya por los Mac, me refiero a las ventas de iPod y canciones de iTunes. A día de hoy carezco de estadísticas actualizadas, pero la última vez que las vi, iPod tenía el 80% de las ventas mundiales de reproductores de música portátiles. Uno de sus puntos de enganche es que tradicionalmente ha sido el único reproductor compatible con las canciones de iTunes (1 euro la canción, 10 euros el disco), el 4º mayor vendedor de música a nivel mundial (y ese dato no está restringido solamente a los vendedores “online”... iTunes es la cuarta tienda que más música vende en todo el mundo, compitiendo directamente con Amazon o HMV). En España la venta de iPods es dramáticamente inferior porque la gente no está dispuesta a pagar ni 1 euro (ni 0,99 céntimos, que es su precio oficial) por escuchar música, y para descargarse MP3s ilegales les sirve cualquier reproductor de esos que venden por 4 duros en las grandes superficies.
No profundizaré en el tema de la piratería, que hoy no me apetece, pero quería poner un caso concreto de cómo la ignorancia y la falta de respeto (dos elementos de la ecuación que produce la piratería) terminan por provocar el retraso tecnológico de una sociedad. De momento, y si Jobs no lo remedia, los españoles no tendremos iPhone, como poco hasta dentro de 5 meses.
En los foros de usuarios de Mac y de amantes de Apple, los usuarios ya estamos de luto mientras nos replanteamos nuestro amor por Steve Jobs.
Pero, ¿qué hace que un mercado tan suculento como el nuestro espante al fabrica
nte del móvil de todos los móviles, aquel por el que la gente dormía en la calle para poder comprarlo cuando se lanzó en USA?. Yo tengo una respuesta a eso: la piratería.España no es un buen territorio para las ventas de Apple, y no ya por los Mac, me refiero a las ventas de iPod y canciones de iTunes. A día de hoy carezco de estadísticas actualizadas, pero la última vez que las vi, iPod tenía el 80% de las ventas mundiales de reproductores de música portátiles. Uno de sus puntos de enganche es que tradicionalmente ha sido el único reproductor compatible con las canciones de iTunes (1 euro la canción, 10 euros el disco), el 4º mayor vendedor de música a nivel mundial (y ese dato no está restringido solamente a los vendedores “online”... iTunes es la cuarta tienda que más música vende en todo el mundo, compitiendo directamente con Amazon o HMV). En España la venta de iPods es dramáticamente inferior porque la gente no está dispuesta a pagar ni 1 euro (ni 0,99 céntimos, que es su precio oficial) por escuchar música, y para descargarse MP3s ilegales les sirve cualquier reproductor de esos que venden por 4 duros en las grandes superficies.
No profundizaré en el tema de la piratería, que hoy no me apetece, pero quería poner un caso concreto de cómo la ignorancia y la falta de respeto (dos elementos de la ecuación que produce la piratería) terminan por provocar el retraso tecnológico de una sociedad. De momento, y si Jobs no lo remedia, los españoles no tendremos iPhone, como poco hasta dentro de 5 meses.
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